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5t^2-70.71t=0
a = 5; b = -70.71; c = 0;
Δ = b2-4ac
Δ = -70.712-4·5·0
Δ = 4999.9041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70.71)-\sqrt{4999.9041}}{2*5}=\frac{70.71-\sqrt{4999.9041}}{10} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70.71)+\sqrt{4999.9041}}{2*5}=\frac{70.71+\sqrt{4999.9041}}{10} $
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